Developing software in the Real World

Extracting the base name of a file in Bash

I have a handy bash script that transcodes videos using Don Meton’s video_transcoding tools. This script was written in a hurry and one limitation it had was that it re-transcoded any source file even if the output file already existed.

The script looked like this:

What it should do is only run if the output file doesn’t exist, so I updated it.

Parameter expansion to the rescue!

I needed to extract the base name and then construct the target filename in order to test for its existence. To extract the base name of the file, I used parameter expansion:

The first line removes the directory portion of file, This works by using the ##[word] expansion which removes the largest prefix pattern which means that for */ it removes everything up to the last / in the string – i.e. any directory paths.

The second line removes the extension from the filename by using the %[word] expansion. This removes the smallest suffix pattern on the string: for .*, it removes the from the last . to the end of the string, and so removes the extension.

I can then create the target by concatenating the output_dir, basename and the .mp4 extension and then test for the target file’s existence.

The final script is now:

It’s a small change, but makes my life easier as I can run my script multiple times without needing to ensure that I’ve deleted any the source files for files that I’ve already transcoded.

Thoughts? Leave a reply

Your email address will not be published. Required fields are marked *